# A coin is tossed 8 times what is the probability of getting at least one head

P(getting one tail) = P(tail) * P(head) * P(head) = 1/2 * 1/2 * 1/2 = 1/ 8. The reason that you have to multiply thrice is because the coin is tossed.

A coin is tossed 7 times. Find the probability of getting more heads than tails in all 7 tosses? Answer: A. If it were: A fair coin is tossed 8 times.

In the experiment of rolling one die, the mutually exclusive outcomes are the die When we flip a coin a very large number of times, we find that we get half heads, and half tails. . The probability for N=2 is therefore 6/16 = 3/ 8. . So the probability to get at least one 3 is, p = 1 - = 3) Five coins are tossed.

A coin is tossed three times. Extra-hard Quant Tests with Brilliant Analytics. Sign up using Google. Relate this to binary numbers. Find the probability of getting : GMAT Problem Solving PS. The sum of the numbers is exactly what we want. But this time, I cannot upvote your answer.

A coin is tossed 7 times. Find the probability of getting more heads than tails in all 7 tosses? Answer: A. If it were: A fair coin is tossed 8 times.

In the experiment of rolling one die, the mutually exclusive outcomes are the die When we flip a coin a very large number of times, we find that we get half heads, and half tails. . The probability for N=2 is therefore 6/16 = 3/ 8. . So the probability to get at least one 3 is, p = 1 - = 3) Five coins are tossed.

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