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# A coin is tossed 8 times what is the probability of getting at least one head

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P(getting one tail) = P(tail) * P(head) * P(head) = 1/2 * 1/2 * 1/2 = 1/ 8. The reason that you have to multiply thrice is because the coin is tossed.
A coin is tossed 7 times. Find the probability of getting more heads than tails in all 7 tosses? Answer: A. If it were: A fair coin is tossed 8 times.
In the experiment of rolling one die, the mutually exclusive outcomes are the die When we flip a coin a very large number of times, we find that we get half heads, and half tails. . The probability for N=2 is therefore 6/16 = 3/ 8. . So the probability to get at least one 3 is, p = 1 - = 3) Five coins are tossed.

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A coin is tossed three times. Extra-hard Quant Tests with Brilliant Analytics. Sign up using Google. Relate this to binary numbers. Find the probability of getting : GMAT Problem Solving PS. The sum of the numbers is exactly what we want. But this time, I cannot upvote your answer.

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What are GMAT Club Tests? Ways to earn points. You saw very well that shayan just wants an answer. Free Word Problem Solver. Hence, in half of the outcomes we will get more heads than tails and in the the other half we will have more tails than heads. Find the probability distribution for X by filling in the table showing each possible value of X along with the probability that value...